email
: Примеры¶
Вот несколько примеров использования пакета email
для чтения, записи и
отправки простых сообщений электронной почты, а также более сложных MIME-сообщений.
Сначала посмотрим, как создать и отправить простое текстовое сообщение (текстовое содержимое и адреса могут содержать символы юникода):
# Import smtplib for the actual sending function
import smtplib
# Import the email modules we'll need
from email.message import EmailMessage
# Open the plain text file whose name is in textfile for reading.
with open(textfile) as fp:
# Create a text/plain message
msg = EmailMessage()
msg.set_content(fp.read())
# me == the sender's email address
# you == the recipient's email address
msg['Subject'] = f'The contents of {textfile}'
msg['From'] = me
msg['To'] = you
# Send the message via our own SMTP server.
s = smtplib.SMTP('localhost')
s.send_message(msg)
s.quit()
Анализ заголовков RFC 822 можно легко выполнить с помощью классов из модуля
parser
:
# Import the email modules we'll need
from email.parser import BytesParser, Parser
from email.policy import default
# If the e-mail headers are in a file, uncomment these two lines:
# with open(messagefile, 'rb') as fp:
# headers = BytesParser(policy=default).parse(fp)
# Or for parsing headers in a string (this is an uncommon operation), use:
headers = Parser(policy=default).parsestr(
'From: Foo Bar <user@example.com>\n'
'To: <someone_else@example.com>\n'
'Subject: Test message\n'
'\n'
'Body would go here\n')
# Now the header items can be accessed as a dictionary:
print('To: {}'.format(headers['to']))
print('From: {}'.format(headers['from']))
print('Subject: {}'.format(headers['subject']))
# You can also access the parts of the addresses:
print('Recipient username: {}'.format(headers['to'].addresses[0].username))
print('Sender name: {}'.format(headers['from'].addresses[0].display_name))
Вот пример отправки MIME-сообщения, содержащего группу семейных изображений, которые могут находиться в каталоге:
# Import smtplib for the actual sending function
import smtplib
# And imghdr to find the types of our images
import imghdr
# Here are the email package modules we'll need
from email.message import EmailMessage
# Create the container email message.
msg = EmailMessage()
msg['Subject'] = 'Our family reunion'
# me == the sender's email address
# family = the list of all recipients' email addresses
msg['From'] = me
msg['To'] = ', '.join(family)
msg.preamble = 'You will not see this in a MIME-aware mail reader.\n'
# Open the files in binary mode. Use imghdr to figure out the
# MIME subtype for each specific image.
for file in pngfiles:
with open(file, 'rb') as fp:
img_data = fp.read()
msg.add_attachment(img_data, maintype='image',
subtype=imghdr.what(None, img_data))
# Send the email via our own SMTP server.
with smtplib.SMTP('localhost') as s:
s.send_message(msg)
Вот пример отправки всего содержимого каталога в виде сообщения электронной почты: [1]
#!/usr/bin/env python3
"""Send the contents of a directory as a MIME message."""
import os
import smtplib
# For guessing MIME type based on file name extension
import mimetypes
from argparse import ArgumentParser
from email.message import EmailMessage
from email.policy import SMTP
def main():
parser = ArgumentParser(description="""\
Send the contents of a directory as a MIME message.
Unless the -o option is given, the email is sent by forwarding to your local
SMTP server, which then does the normal delivery process. Your local machine
must be running an SMTP server.
""")
parser.add_argument('-d', '--directory',
help="""Mail the contents of the specified directory,
otherwise use the current directory. Only the regular
files in the directory are sent, and we don't recurse to
subdirectories.""")
parser.add_argument('-o', '--output',
metavar='FILE',
help="""Print the composed message to FILE instead of
sending the message to the SMTP server.""")
parser.add_argument('-s', '--sender', required=True,
help='The value of the From: header (required)')
parser.add_argument('-r', '--recipient', required=True,
action='append', metavar='RECIPIENT',
default=[], dest='recipients',
help='A To: header value (at least one required)')
args = parser.parse_args()
directory = args.directory
if not directory:
directory = '.'
# Create the message
msg = EmailMessage()
msg['Subject'] = f'Contents of directory {os.path.abspath(directory)}'
msg['To'] = ', '.join(args.recipients)
msg['From'] = args.sender
msg.preamble = 'You will not see this in a MIME-aware mail reader.\n'
for filename in os.listdir(directory):
path = os.path.join(directory, filename)
if not os.path.isfile(path):
continue
# Guess the content type based on the file's extension. Encoding
# will be ignored, although we should check for simple things like
# gzip'd or compressed files.
ctype, encoding = mimetypes.guess_type(path)
if ctype is None or encoding is not None:
# No guess could be made, or the file is encoded (compressed), so
# use a generic bag-of-bits type.
ctype = 'application/octet-stream'
maintype, subtype = ctype.split('/', 1)
with open(path, 'rb') as fp:
msg.add_attachment(fp.read(),
maintype=maintype,
subtype=subtype,
filename=filename)
# Now send or store the message
if args.output:
with open(args.output, 'wb') as fp:
fp.write(msg.as_bytes(policy=SMTP))
else:
with smtplib.SMTP('localhost') as s:
s.send_message(msg)
if __name__ == '__main__':
main()
Вот пример распаковки MIME-сообщения, подобного приведенному выше, в каталог файлов:
#!/usr/bin/env python3
"""Unpack a MIME message into a directory of files."""
import os
import email
import mimetypes
from email.policy import default
from argparse import ArgumentParser
def main():
parser = ArgumentParser(description="""\
Unpack a MIME message into a directory of files.
""")
parser.add_argument('-d', '--directory', required=True,
help="""Unpack the MIME message into the named
directory, which will be created if it doesn't already
exist.""")
parser.add_argument('msgfile')
args = parser.parse_args()
with open(args.msgfile, 'rb') as fp:
msg = email.message_from_binary_file(fp, policy=default)
try:
os.mkdir(args.directory)
except FileExistsError:
pass
counter = 1
for part in msg.walk():
# multipart/* are just containers
if part.get_content_maintype() == 'multipart':
continue
# Applications should really sanitize the given filename so that an
# email message can't be used to overwrite important files
filename = part.get_filename()
if not filename:
ext = mimetypes.guess_extension(part.get_content_type())
if not ext:
# Use a generic bag-of-bits extension
ext = '.bin'
filename = f'part-{counter:03d}{ext}'
counter += 1
with open(os.path.join(args.directory, filename), 'wb') as fp:
fp.write(part.get_payload(decode=True))
if __name__ == '__main__':
main()
Вот пример создания HTML-сообщения с альтернативной версией обычного текста. Чтобы сделать вещи немного интереснее, мы включаем связанное изображение в html- часть, и мы сохраняем копию того, что мы собираемся отправить на диск, а также отправлять его.
Если бы нам послали сообщение из последнего примера, вот один из способов, которым мы могли бы его обработать:
В ответ на запрос выводится следующий результат:
To: Penelope Pussycat <penelope@example.com>, Fabrette Pussycat <fabrette@example.com>
From: Pepé Le Pew <pepe@example.com>
Subject: Ayons asperges pour le déjeuner
Salut!
Cela ressemble à un excellent recipie[1] déjeuner.
Сноски
[1] | Спасибо Matthew Dixon Cowles за оригинальное вдохновение и примеры. |